Optimal. Leaf size=661 \[ \frac {27 a^2 (26 A b-5 a B) (e x)^{5/2} \sqrt {a+b x^3}}{5824 b e}+\frac {81 \left (1+\sqrt {3}\right ) a^3 (26 A b-5 a B) e \sqrt {e x} \sqrt {a+b x^3}}{11648 b^{5/3} \left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )}+\frac {3 a (26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{3/2}}{728 b e}+\frac {(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}-\frac {81 \sqrt [4]{3} a^{10/3} (26 A b-5 a B) e \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} E\left (\cos ^{-1}\left (\frac {\sqrt [3]{a}+\left (1-\sqrt {3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{11648 b^{5/3} \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {27\ 3^{3/4} \left (1-\sqrt {3}\right ) a^{10/3} (26 A b-5 a B) e \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} F\left (\cos ^{-1}\left (\frac {\sqrt [3]{a}+\left (1-\sqrt {3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{23296 b^{5/3} \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}} \]
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Rubi [A]
time = 0.54, antiderivative size = 661, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 6, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {470, 285, 335,
314, 231, 1895} \begin {gather*} -\frac {27\ 3^{3/4} \left (1-\sqrt {3}\right ) a^{10/3} e \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} (26 A b-5 a B) F\left (\text {ArcCos}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}{\left (1+\sqrt {3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{23296 b^{5/3} \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {81 \sqrt [4]{3} a^{10/3} e \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} (26 A b-5 a B) E\left (\text {ArcCos}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}{\left (1+\sqrt {3}\right ) \sqrt [3]{b} x+\sqrt [3]{a}}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{11648 b^{5/3} \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}+\frac {81 \left (1+\sqrt {3}\right ) a^3 e \sqrt {e x} \sqrt {a+b x^3} (26 A b-5 a B)}{11648 b^{5/3} \left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )}+\frac {27 a^2 (e x)^{5/2} \sqrt {a+b x^3} (26 A b-5 a B)}{5824 b e}+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2} (26 A b-5 a B)}{260 b e}+\frac {3 a (e x)^{5/2} \left (a+b x^3\right )^{3/2} (26 A b-5 a B)}{728 b e}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e} \end {gather*}
Antiderivative was successfully verified.
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Rule 231
Rule 285
Rule 314
Rule 335
Rule 470
Rule 1895
Rubi steps
\begin {align*} \int (e x)^{3/2} \left (a+b x^3\right )^{5/2} \left (A+B x^3\right ) \, dx &=\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}-\frac {\left (-13 A b+\frac {5 a B}{2}\right ) \int (e x)^{3/2} \left (a+b x^3\right )^{5/2} \, dx}{13 b}\\ &=\frac {(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}+\frac {(3 a (26 A b-5 a B)) \int (e x)^{3/2} \left (a+b x^3\right )^{3/2} \, dx}{104 b}\\ &=\frac {3 a (26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{3/2}}{728 b e}+\frac {(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}+\frac {\left (27 a^2 (26 A b-5 a B)\right ) \int (e x)^{3/2} \sqrt {a+b x^3} \, dx}{1456 b}\\ &=\frac {27 a^2 (26 A b-5 a B) (e x)^{5/2} \sqrt {a+b x^3}}{5824 b e}+\frac {3 a (26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{3/2}}{728 b e}+\frac {(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}+\frac {\left (81 a^3 (26 A b-5 a B)\right ) \int \frac {(e x)^{3/2}}{\sqrt {a+b x^3}} \, dx}{11648 b}\\ &=\frac {27 a^2 (26 A b-5 a B) (e x)^{5/2} \sqrt {a+b x^3}}{5824 b e}+\frac {3 a (26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{3/2}}{728 b e}+\frac {(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}+\frac {\left (81 a^3 (26 A b-5 a B)\right ) \text {Subst}\left (\int \frac {x^4}{\sqrt {a+\frac {b x^6}{e^3}}} \, dx,x,\sqrt {e x}\right )}{5824 b e}\\ &=\frac {27 a^2 (26 A b-5 a B) (e x)^{5/2} \sqrt {a+b x^3}}{5824 b e}+\frac {3 a (26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{3/2}}{728 b e}+\frac {(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}-\frac {\left (81 a^3 (26 A b-5 a B)\right ) \text {Subst}\left (\int \frac {\left (-1+\sqrt {3}\right ) a^{2/3} e^2-2 b^{2/3} x^4}{\sqrt {a+\frac {b x^6}{e^3}}} \, dx,x,\sqrt {e x}\right )}{11648 b^{5/3} e}-\frac {\left (81 \left (1-\sqrt {3}\right ) a^{11/3} (26 A b-5 a B) e\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+\frac {b x^6}{e^3}}} \, dx,x,\sqrt {e x}\right )}{11648 b^{5/3}}\\ &=\frac {27 a^2 (26 A b-5 a B) (e x)^{5/2} \sqrt {a+b x^3}}{5824 b e}+\frac {81 \left (1+\sqrt {3}\right ) a^3 (26 A b-5 a B) e \sqrt {e x} \sqrt {a+b x^3}}{11648 b^{5/3} \left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )}+\frac {3 a (26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{3/2}}{728 b e}+\frac {(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}-\frac {81 \sqrt [4]{3} a^{10/3} (26 A b-5 a B) e \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} E\left (\cos ^{-1}\left (\frac {\sqrt [3]{a}+\left (1-\sqrt {3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{11648 b^{5/3} \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {27\ 3^{3/4} \left (1-\sqrt {3}\right ) a^{10/3} (26 A b-5 a B) e \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} F\left (\cos ^{-1}\left (\frac {\sqrt [3]{a}+\left (1-\sqrt {3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{23296 b^{5/3} \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 4 in
optimal.
time = 10.11, size = 99, normalized size = 0.15 \begin {gather*} \frac {x (e x)^{3/2} \sqrt {a+b x^3} \left (5 B \left (a+b x^3\right )^3 \sqrt {1+\frac {b x^3}{a}}+a^2 (26 A b-5 a B) \, _2F_1\left (-\frac {5}{2},\frac {5}{6};\frac {11}{6};-\frac {b x^3}{a}\right )\right )}{65 b \sqrt {1+\frac {b x^3}{a}}} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains complex when optimal does not.
time = 0.34, size = 6202, normalized size = 9.38
method | result | size |
risch | \(\text {Expression too large to display}\) | \(1188\) |
elliptic | \(\text {Expression too large to display}\) | \(1410\) |
default | \(\text {Expression too large to display}\) | \(6202\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] Result contains complex when optimal does not.
time = 61.29, size = 308, normalized size = 0.47 \begin {gather*} \frac {A a^{\frac {5}{2}} e^{\frac {3}{2}} x^{\frac {5}{2}} \Gamma \left (\frac {5}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {5}{6} \\ \frac {11}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {11}{6}\right )} + \frac {2 A a^{\frac {3}{2}} b e^{\frac {3}{2}} x^{\frac {11}{2}} \Gamma \left (\frac {11}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {11}{6} \\ \frac {17}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {17}{6}\right )} + \frac {A \sqrt {a} b^{2} e^{\frac {3}{2}} x^{\frac {17}{2}} \Gamma \left (\frac {17}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {17}{6} \\ \frac {23}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {23}{6}\right )} + \frac {B a^{\frac {5}{2}} e^{\frac {3}{2}} x^{\frac {11}{2}} \Gamma \left (\frac {11}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {11}{6} \\ \frac {17}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {17}{6}\right )} + \frac {2 B a^{\frac {3}{2}} b e^{\frac {3}{2}} x^{\frac {17}{2}} \Gamma \left (\frac {17}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {17}{6} \\ \frac {23}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {23}{6}\right )} + \frac {B \sqrt {a} b^{2} e^{\frac {3}{2}} x^{\frac {23}{2}} \Gamma \left (\frac {23}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {23}{6} \\ \frac {29}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {29}{6}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \left (B\,x^3+A\right )\,{\left (e\,x\right )}^{3/2}\,{\left (b\,x^3+a\right )}^{5/2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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